Try each question on your own first. Use the Show Answer button only after you have selected your option, then read the explanation and revise the related concept from your chapter notes.
17. Domestic electric circuits are always wired in parallel rather than series because:
A. In parallel, if one appliance fails, others continue working independently
B. Series wiring requires thicker copper wires
C. Parallel wiring increases total resistance
D. In series, voltage across each appliance increases
Answer: A. In parallel, if one appliance fails, others continue working independently
Explanation: Parallel circuits give each appliance full line voltage (220V) and independent switches so one faulty device doesn't open the whole circuit.
18. According to Joule's Law of Heating, the heat (H) generated in a resistor is given by the formula:
A. H = I × R × t
B. H = I^2 × R × t
C. H = V × I^2 × t
D. H = I × R^2 × t
Answer: B. H = I^2 × R × t
Explanation: Joule's Law states H = I^2 R t, where I is current, R is resistance, and t is time.
19. Which metal is almost exclusively used for filaments of electric bulbs due to its very high melting point (~3380 °C)?
A. Copper
B. Tungsten
C. Aluminum
D. Iron
Answer: B. Tungsten
Explanation: Tungsten has an extremely high melting point and high resistivity, enabling it to glow white-hot without melting.
20. Electric bulbs are usually filled with chemically inactive gases like:
A. Oxygen and Hydrogen
B. Nitrogen and Argon
C. Carbon dioxide and Helium
D. Chlorine and Fluorine
Answer: B. Nitrogen and Argon
Explanation: Inactive gases like argon and nitrogen prevent oxidation and prolong filament life.
21. An electric fuse is a safety device connected in:
A. Parallel with live wire
B. Series with live wire
C. Series with neutral wire
D. Parallel with earth wire
Answer: B. Series with live wire
Explanation: Fuse wire is connected in series with the live wire so that excess current melts it, breaking the circuit instantly.
22. The rate at which electrical energy is consumed in an electric circuit is called:
A. Electric Current
B. Potential Difference
C. Electric Power
D. Resistance
Answer: C. Electric Power
Explanation: Power P = Energy / time = V × I, representing rate of electrical work done.
23. The SI unit of electric power is:
A. Joule
B. Watt (W)
C. Kilowatt-hour
D. Ampere
Answer: B. Watt (W)
Explanation: 1 Watt is the power consumed by a device carrying 1 A current at 1 V potential difference (1 W = 1 V × 1 A = 1 J/s).
24. Commercial unit of electrical energy is kilowatt-hour (kWh), commonly called 'unit'. 1 kWh is equal to:
A. 3.6 × 10^5 J
B. 3.6 × 10^6 J
C. 1.6 × 10^6 J
D. 36 × 10^6 J
Answer: B. 3.6 × 10^6 J
Explanation: 1 kWh = 1000 W × 3600 s = 3,600,000 J = 3.6 × 10^6 Joules.
25. An electric heater rated 1000 W operates on a 220 V line. The current drawn by the heater is approximately:
A. 4.55 A
B. 2.2 A
C. 10 A
D. 0.22 A
Answer: A. 4.55 A
Explanation: Current I = P / V = 1000 W / 220 V = 4.545 A ≈ 4.55 A.
26. If the length of a wire is stretched to double its original length keeping volume constant, its new resistance becomes:
A. 2 times
B. 4 times
C. Half
D. 8 times
Answer: B. 4 times
Explanation: Stretching to double length halves area A. Since R = ρ(l/A), new resistance R' = ρ(2l/(A/2)) = 4 R.
27. A variable resistor used in circuits to change current without changing voltage source is called a:
A. Galvanometer
B. Rheostat
C. Voltmeter
D. Transformer
Answer: B. Rheostat
Explanation: A rheostat allows manual variation of circuit resistance to regulate electrical current flow.
28. Two electric bulbs rated (220 V, 100 W) and (220 V, 60 W) are connected in parallel to a 220 V supply. Which bulb draws more current?
A. 60 W bulb
B. 100 W bulb
C. Both draw equal current
D. Neither draws current
Answer: B. 100 W bulb
Explanation: Since I = P / V and V is constant in parallel, the higher power bulb (100 W) draws more current.
29. Which mathematical formula correctly represents electric power?
A. P = V × I
B. P = I^2 × R
C. P = V^2 / R
D. All of the above
Answer: D. All of the above
Explanation: Using Ohm's law V = IR, electric power can be expressed as P = VI = I^2 R = V^2 / R.
30. When a wire of resistance R is cut into 5 equal parts and connected in parallel, the equivalent resistance R' gives a ratio R/R' equal to:
A. 1/25
B. 1/5
C. 5
D. 25
Answer: D. 25
Explanation: Each piece has resistance R/5. In parallel, 1/R' = 5/(R/5) = 25/R. Thus R' = R/25, making R/R' = 25.
This page contains a chapter-wise objective practice set. Try the questions without checking the answer first, then use the explanation to understand the point you missed. The current page contains 30 questions, so you can practise in smaller sets when you are revising.
Quick revision tip
After the practice set, write down the question numbers you missed and revise only those concepts once more. This makes MCQ practice more useful than repeatedly attempting the same questions without reviewing mistakes.